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avra: add branching instructions

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Virgil Dupras 4 年前
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4b9712a224
共有 4 个文件被更改,包括 148 次插入10 次删除
  1. +137
    -9
      apps/zasm/avr.asm
  2. +4
    -0
      tools/tests/avra/test1.asm
  3. +1
    -1
      tools/tests/avra/test1.expected
  4. +6
    -0
      tools/tests/unit/test_core.asm

+ 137
- 9
apps/zasm/avr.asm 查看文件

@@ -8,8 +8,32 @@
; categories, and then alphabetically. Categories are ordered so that the 8bit
; opcodes come first, then the 16bit ones. 0xff ends the chain
instrNames:
; Branching instructions. They are all shortcuts to BRBC/BRBS. Their respective
; bits are listed in instrBRBits. These are not in alphabetical order, but
; rather in "bit order". All "bit set" instructions first (10th bit clear), then
; all "bit clear" ones (10th bit set). Inside this order, they're then in "sss"
; order (bit number alias for BRBC/BRBS)
.db "BRCS", 0
.db "BREQ", 0
.db "BRMI", 0
.db "BRVS", 0
.db "BRLT", 0
.db "BRHS", 0
.db "BRTS", 0
.db "BRIE", 0
.db "BRCC", 0
.db "BRNE", 0
.db "BRPL", 0
.db "BRVC", 0
.db "BRGE", 0
.db "BRHC", 0
.db "BRTC", 0
.db "BRID", 0
.equ I_BRBS 16
.db "BRBS", 0
.db "BRBC", 0
; Rd(5) + Rr(5)
.equ I_ADC 0
.equ I_ADC 18
.db "ADC", 0
.db "ADD", 0
.db "AND", 0
@@ -24,7 +48,7 @@ instrNames:
.db "SBC", 0
.db "SUB", 0
; no arg
.equ I_BREAK 13
.equ I_BREAK 31
.db "BREAK", 0
.db "CLC", 0
.db "CLH", 0
@@ -52,7 +76,7 @@ instrNames:
.db "SLEEP", 0
.db "WDR", 0
; Rd(5)
.equ I_ASR 39
.equ I_ASR 57
.db "ASR", 0
.db "COM", 0
.db "DEC", 0
@@ -134,6 +158,25 @@ instrUpMasks2:
.db 0b10010100, 0b00000010 ; SWAP
.db 0b10010010, 0b00000100 ; XCH

instrBRBits:
; 1st bit is 3rd bit of MSB and the other 3 are the lower bits of LSB
.db 0b0000 ; BRCS
.db 0b0001 ; BREQ
.db 0b0010 ; BRMI
.db 0b0011 ; BRVS
.db 0b0100 ; BRLT
.db 0b0101 ; BRHS
.db 0b0110 ; BRTS
.db 0b0111 ; BRIE
.db 0b1000 ; BRCC
.db 0b1001 ; BRNE
.db 0b1010 ; BRPL
.db 0b1011 ; BRVC
.db 0b1100 ; BRGE
.db 0b1101 ; BRHC
.db 0b1110 ; BRTC
.db 0b1111 ; BRID

; Same signature as getInstID in instr.asm
; Reads string in (HL) and returns the corresponding ID (I_*) in A. Sets Z if
; there's a match.
@@ -172,6 +215,8 @@ getInstID:
parseInstruction:
; BC, during .spit, is ORred to the spitted opcode.
ld bc, 0
cp I_ADC
jp c, .BR
cp I_BREAK
jr c, .spitRd5Rr5
cp I_ASR
@@ -207,8 +252,7 @@ parseInstruction:
or b
ld b, a
ld a, d ; restore A
ld hl, instrUpMasks1
call addHL
call .getUp1
; now that's our MSB
jr .spitMSB
.spit:
@@ -225,6 +269,77 @@ parseInstruction:
xor a ; ensure Z, set success
ret

; Spit a branching mnemonic.
.BR:
; While we have our index in A, let's settle B straight: Our base
; upcode is 0b11110000 for "bit set" types and 0b11110100 for "bit
; clear" types. However, we'll have 2 left shift operation done on B
; later on, so we need those bits shifted right.
ld b, 0b111100
cp I_BRBS
jr z, .rdBRBS
jr nc, .rdBRBC
; We have an alias. Our "sss" value is index & 0b111
; Before we get rid of that 3rd bit, let's see, is it set? if yes, we'll
; want to increase B
bit 3, a
jr z, .skip1 ; 3rd bit unset
inc b
.skip1:
and 0b111
ld c, a
.spitBR2:
call readWord
ret nz
call parseExpr
ret nz
; IX contains an absolute value. Turn this into a -64/+63 relative
; value by subtracting PC from it. However, before we do that, let's
; add 0x7f to it, which we'll remove later. This will simplify bounds
; checks. (we use 7f instead of 3f because we deal in bytes here, not
; in words)
push ix \ pop hl
ld de, 0x7f
add hl, de ; Carry cleared
ex de, hl
call zasmGetPC ; --> HL
; The relative value is actually not relative to current PC, but to
; PC after the execution of this branching op. Increase HL by 2.
inc hl \ inc hl
ex de, hl
sbc hl, de
jp c, unsetZ ; Carry? error
ld de, 0x7f
sbc hl, de
; We're within bounds! However, our value in L is the number of
; relative *bytes*. The value we put there is the number of words.
; Thefore, relevant bits are 7:1
ld a, l
sla a \ rl b
sla a \ rl b
; k is now shifted by 3, two of those bits being in B. Let's OR A and
; C and we have our LSB ready to go.
or c
call ioPutB
; Good! MSB now. B is already good to go.
ld a, b
jp ioPutB
.rdBRBC:
; In addition to reading "sss", we also need to inc B so that our base
; upcode becomes 0b111101
inc b
.rdBRBS:
call readWord
ret nz
call parseExpr
ld a, 7
call .IX2A
ret nz
ld c, a
call readComma
ret nz
jr .spitBR2

; local routines
; place number in A in BC at position .......d dddd....
; BC is assumed to be 0
@@ -233,6 +348,13 @@ parseInstruction:
rl b
ld c, a
ret

; Fetch a 8-bit upcode specified by instr index in A and set that upcode in HL
.getUp1:
sub I_ADC
ld hl, instrUpMasks1
jp addHL

; Fetch a 16-bit upcode specified by instr index in A and set that upcode in HL
.getUp2:
sub I_BREAK
@@ -251,13 +373,19 @@ parseInstruction:
inc hl
call parseDecimal
ret nz
ld a, 31
jr .IX2A

; Put IX's LSB into A and, additionally, ensure that the new value is <=
; than what was previously in A.
; Z for success.
.IX2A:
push ix \ pop hl
cp l
jp c, unsetZ ; A < L
ld a, h
or a
ret nz ; should be zero
ld a, l
cp 32
jp nc, unsetZ ; must be < 32
; we're good!
cp a ; ensure Z
; Z set from "or a"
ret

+ 4
- 0
tools/tests/avra/test1.asm 查看文件

@@ -1,5 +1,9 @@
add r1, r31
ret
foo:
sleep
break
breq bar
asr r20
bar:
brbs 6, foo

+ 1
- 1
tools/tests/avra/test1.expected 查看文件

@@ -1 +1 @@
•ˆ•˜•E•
•ˆ•˜• ðE•Þó

+ 6
- 0
tools/tests/unit/test_core.asm 查看文件

@@ -51,6 +51,12 @@ test:
jp nz, fail
call nexttest

; test that AND affects the Z flag
ld a, 0x69
and 0x80
jp nz, fail
call nexttest

; success
xor a
halt


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