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shell: handle inputs with interrupts

pull/10/head
Virgil Dupras před 5 roky
rodič
revize
ac22a206ae
1 změnil soubory, kde provedl 48 přidání a 32 odebrání
  1. +48
    -32
      parts/shell/shell.asm

+ 48
- 32
parts/shell/shell.asm Zobrazit soubor

@@ -27,8 +27,10 @@ BUFIDX .equ INPTBUF+BUFSIZE
; *** CODE ***
jr init

.fill 0x38-$
jr handleInterrupt

init:
; disable interrupts we don't need them
di

; setup stack
@@ -39,12 +41,16 @@ init:
xor a
ld (BUFIDX), a ; starts at 0

; RC2014's serial I/O is based on interrupt mode 1. We'd prefer im 2,
; but for now, let's go with the simpler im 1.
im 1

; setup ACIA
; CR7 (1) - Receive Interrupt disabled
; CR7 (1) - Receive Interrupt enabled
; CR6:5 (00) - RTS low, transmit interrupt disabled.
; CR4:2 (101) - 8 bits + 1 stop bit
; CR1:0 (10) - Counter divide: 64
ld a, 0b00010110
ld a, 0b10010110
out (ACIA_CTL), a

; print prompt
@@ -52,11 +58,42 @@ init:
call printstr
call printcrlf

; alright, ready to receive
ei

mainloop:
call readc
call chkbuf
jr mainloop

; read char in the ACIA and put it in the read buffer
handleInterrupt:
push af
push hl

; Read our character from ACIA into our BUFIDX
in a, (ACIA_CTL)
bit 0, a ; is our ACIA rcv buffer full?
jr z, .end ; no? a interrupt was triggered for nothing.

call getbufptr ; HL set, A set
; is our input buffer full? If yes, we don't read anything. Something
; is wrong: we don't process data fast enough.
cp BUFSIZE
jr z, .end ; if BUFIDX == BUFSIZE, our buffer is full.

; increase our buf ptr while we still have it in A
inc a
ld (BUFIDX), a

in a, (ACIA_IO)
ld (hl), a

.end:
pop hl
pop af
ei
reti

; spits character in A in port SER_OUT
printc:
push af
@@ -85,43 +122,17 @@ printcrlf:
call printc
ret

; wait until a char is read in the ACIA and put it in the read buffer
readc:
; first thing first: is our input buffer full? If yes, we don't even
; bother reading the ACIA. Something is wrong: we don't process data
; fast enough.
ld a, (BUFIDX)
cp BUFSIZE
ret z ; if BUFIDX == BUFSIZE, our buffer is full.

call getbufptr

; increase our buf ptr while we still have it in A
inc a
ld (BUFIDX), a

.loop:
; Read our character from ACIA into our BUFIDX
in a, (ACIA_CTL)
bit 0, a ; is our ACIA rcv buffer full?
jr z, .loop ; no? loop

in a, (ACIA_IO)
ld (hl), a

ret

; check if the input buffer is full or ends in CR or LF. If it does, prints it
; back and empty it.
chkbuf:
ld a, (BUFIDX)
call getbufptr
cp 0
ret z ; BUFIDX is zero? nothing to check.

cp BUFSIZE
jr z, .do ; if BUFIDX == BUFSIZE? do!

call getbufptr
; our previous char is in BUFIDX - 1. Fetch this
dec hl
ld a, (hl) ; now, that's our char we have in A
@@ -149,12 +160,17 @@ chkbuf:
ret

; Set current buffer pointer in HL. The buffer pointer is where our *next* char
; will be written.
; will be written. A is set to the value of (BUFIDX)
getbufptr:
push bc

ld a, (BUFIDX)
ld hl, INPTBUF
xor b
ld c, a
add hl, bc ; hl now points to INPTBUF + BUFIDX

pop bc
ret

; *** DATA ***


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